Question

find the value of p for which one root of the quadratic equation px2-14x+8=0 is 6 times the other​

Answer 1

Answer:

px isthe answer kyunki px2

Answer 2

Answer:

⇒ The given quadratic equation is px

2

−14x+8=0

⇒ Let the root be α then other root will be 6α

⇒ Sum of the roots =

a

−b

⇒ α+6α=

p

−(−14)

⇒ 7α=

p

14

∴ α=

p

2

-------- ( 1 )

⇒ Product of the roots =

a

c

⇒ α.6α=

p

8

⇒ 6α

2

=

p

8

⇒ 6(

p

2

)

2

=

p

8

[ From ( 1 ) ]

⇒ 6×

p

2

2

=

p

8

∴ p=3