find the value of p for which one root of the quadratic equation px2-14x+8=0 is 6 times the other
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2
Answer:
px isthe answer kyunki px2
Answered by
0
Answer:
⇒ The given quadratic equation is px
2
−14x+8=0
⇒ Let the root be α then other root will be 6α
⇒ Sum of the roots =
a
−b
⇒ α+6α=
p
−(−14)
⇒ 7α=
p
14
∴ α=
p
2
-------- ( 1 )
⇒ Product of the roots =
a
c
⇒ α.6α=
p
8
⇒ 6α
2
=
p
8
⇒ 6(
p
2
)
2
=
p
8
[ From ( 1 ) ]
⇒ 6×
p
2
2
=
p
8
∴ p=3
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