Question

Find the value of p, for which one root of the quadratic equation px^2-14x+8 is 6 times the other. ​

Answer 1

Answer:

2-14×+8is 6 times the is 14×2+8÷6 what answer you get Then send me I know that my answer is correct are not

Answer 2

Answer:

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Given -

px² - 14x + 8 = 0

Let one of the roots be 'a' , then the other root is '6a'

a + 6a = 14/p

7a = 14/p

a = 2/p ---(i)

a x 6a = 8/p

6a² = 8/p

Plugging the value of a from eq (i),

6 x (2/p)² = 8/p

6 x 4/p² = 8/p

24/p = 8 (Cancelling 'p' from both the sides)

8p = 24

p = 3

So required value of 'p' is 3

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