Math, asked by Anonymous, 1 year ago

find the value of p for which one root of the quadratic equation p x square - 14 x + 8 is equal to zero is 6

Answers

Answered by Pythagaros

Px2 - 14x + 8 = 0

One root = 6

So, p(6)² - 14(6) + 8 = 0

36p - 84 + 8 = 0

36p - 76 =0

36p = 76

p = 76/36

p = 19/9

Anonymous: is this answer is write

Pythagaros: But why..

Anonymous: yes this question is from polynomial

Pythagaros: Ohkk then... Nd sorry

Answered by Anonymous

$\huge\mathfrak{HoLa\: Mate!!!}$

Ur AnSWeR iS iN attachment✔✔

Hope That wiLL heLp uhh

Attachments:

Anonymous: thank uu..

Pythagaros: Why u take 6 alpha ??

Anonymous: because they given equation is 6

Anonymous: i didn't understand that last step

Anonymous: from so,

Anonymous: ohh kk

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