Math, asked by Ayush9009, 11 months ago

Find the value of p for which one root of the quadratic equation x square - 14 x + 8 = 20 x 6 times the other

Answers

Answered by HEMANTHKUMAR007
4

Let the other root be {x}

Therefore, the one root is {6x}

Now, Given equation is

{x^2-14x+8=0}

From this equation,

a = 1; b = -14; c = 8

Product of roots = {\dfrac{c}{a}}

=> {x\times{6x}} = {\dfrac{8}{1}}

=> {6x^2 = 8}

=> {x^2 = 4/3}

=> {x = 2/\sqrt{3}}

Similar questions