Question

Find the value of p for which one root of the quardatic equation px²-14x+8=0 is 6 times the other​

Answer 1

Given 

px^2-14x+8=0

let  a and b be the roots of the equation

b=6a

sum of roots = -b/a

product of roots = c/a

here a=p , b=-14 , c=8

a+b=14/p

ab=8/p

a+6a=14/p

7a=14/p

a=2/p

a*6a=8/p

6a^2=8/p

3a^2=4/p

3*(2/p)^2=4/p

3*4/p^2=4/p

p=3

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jio dhan dhana dhan

Answer 2

Hi buddy here is ur answer

Look below at the pic....

Mark as the braniliest answer if it helps...

Regards

Brainer mathlete