find the value of p for which one zero of the polynomial x2-(p2-4)x+8 is additive inverse of each other
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P = 2 or -2
P = 2 or -2
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Given :- find the value of p for which one zero of the polynomial x2-(p2-4)x+8 is additive inverse of each other ?
Solution :-
→ p(x) = x² - (p² - 4)x + 8
we know that, additive inverse is a number that when added to a given number gives zero .
so,
→ sum of both zeroes = 0
then,
→ sum of zeros = (-b/a)
given that,
- b = -(p² - 4)
- a = 1
therefore,
→ (-b/a) = 0
→ p² - 4/1 = 0
→ p² - 4 = 0
→ p² = 4
→ p = ±2 (Ans.)
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