Question

Find the value of p for which
${8}^{p} \div {2}^{ - 3} = {2}^{9}$
​

Answer 1

Step-by-step explanation:

8^p /2^-3 =2^9

8^p = 2^9 × 2^-3

8^p = 2^6 [ because base same powers will add]

8^p = 64

8^p = 8^2

p = 2

So, the value of p = 2

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