Find the value of p for which the curves x^2=9p(9-y)
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Given, equations of curves are x2 = 9p(9 - y) ....(i) and x2 = p(y + 1) .....(ii) As, these curves cut each other at right angle, therefore their tangent at point of intersection are perpendicular to each other. So, let us first find the point of intersection and slope of tangents to the curves. From Eqs. (i) and (ii), we get 9p(9 - y) = p(y + 1) 9(9 - y) = y + 1Read more on Sarthaks.com - https://www.sarthaks.com/201586/find-the-value-of-p-for-which-the-curves-x-2-9p-9-y-and-x-2-p-y-1-cut-each-other-at-right-angles
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Hi mate...!!!
Here is your answer... ****
Pls refer to attachment
Pls refer to attachment Hence the value of P =6
Hope you understand
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