Find the value of p for which the distance between the points A(3,-5)and B (p,2)is √58units
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Answer:6
Step-by-step explanation:
Given:- A(3,-5) & B(p,2)
√58=√(3–p)^2+(-7)^2
Sq both sides
58=(3-p)^2+49
58=9+p^2-6p+49
58-49-9=p(p-6)
0=p(p-6)
p=0 or p-6=0
p=0 or p=6
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