find the value of p for which the distance between the points
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3 or -9
Step-by-step explanation:
10 = √(2 - 10)² + (-3-y)²
squaring both sides
100 = (-8)² + (9 + y² + 6y)
100 = 64 +9 + y² + 6y
y² + 6y - 27 = 0
y² + 9y - 3y - 27 = 0
y(y + 9) -3(y + 9) = 0
(y-3)(y+9) = 0
y=3 or y=-9
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hope it's help u.......
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