Question

find the value of p for which the equation 4x^2 - 3px+3 has real roots

Answer 1

Answer:

Step-by-step explanation:

After Comparing the equation with ax^2 +bx+ c =0

Since the equation has real roots

b^2 - 4ac >= 0. (Ps: >= stands for

(-3p)^2 - 4×4×3>=0 greater than or

equal to)

9p^2 - 48 >= 0

p >= √48/√9

p>= 4√3/3

Answer 2

4x²-3px+3

b²-4ac>0

[-3p]²-4*4*3>0

9p²-48>0

9p²>48

p²>48/9

p>√48/3

p>4√3/3