Find the value of p for which the equation px^2-5x+p =0has equal roots.
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Answered by
8
Hi !
px² - 5x + p = 0
a = p , b = -5 , c = p
As the equation has equal roots,
b² - 4ac = 0
(-5)² - 4*p*p = 0
25 - 4p² = 0
4p² = 25
p² = 25/4
p = ± 5/2
px² - 5x + p = 0
a = p , b = -5 , c = p
As the equation has equal roots,
b² - 4ac = 0
(-5)² - 4*p*p = 0
25 - 4p² = 0
4p² = 25
p² = 25/4
p = ± 5/2
Answered by
1
for equal root D must be zero
D=b^2-4ac
-5^2-4×p×p=0
25-4p^2=0
-4p^2=-25
p^2=25/4
p=+_5/2
D=b^2-4ac
-5^2-4×p×p=0
25-4p^2=0
-4p^2=-25
p^2=25/4
p=+_5/2
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