Question

Find the value of p for which the equation px^2 -6x-2 =0 has real roots

Answer 1

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☞ P ≤ 9/2

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✭ Set of values of P ?

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≫ Px² - 6x -2 = 0

Given that it has real roots .

We know that if we have a quadratic equation

→ ax² + bx + c = 0 and it's roots are real so it's discriminate (D) be greater then or equal to zero

D = b² - 4ac ≥0

Compare both of the equation

→ a = P , b = -6 and c = -2

Now ,its discriminate (D) ≥0,

→ (-6)² - 4×P ×(-2) ≥0

→ 36 + 8P≥ 0

→ 8P ≥ -36

→ P ≥ -36/8

→ P ≥ -9/2

Or

→ P≤ 9/2

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