Question

Find the value of p for which the equation px-5x+p=0 has equal roots

Answer 1

condition for equal roots:
D=0
=> b^2 -4ac= 0
Here ,
a= p
b= -5
and , c= p
On putting these values,
(-5)^2 -4×p×p =0
=> 25 - 4p^2 = 0
=> 25 = 4p^2
=> 25/4 = p^2
=> +-√25/4 = p
=> p = +5/2 and -5/2

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Answer 2

for having equal roots a equation must have this condition
b^2-4×a×c=0
5^2-4×p×p=0
25-4p^2=0
-4p^2=-25
p^2=-25/-4
P=✓25/4
P=5/2
therefore the value of P is 5/2 for having equal roots in the equation.
hope it works for you