Find the value of p for which the equation px2-5x+p=0 has equal roots
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px²-5x+p
where,
a=p
b=-5
c=p
and, it has two equal roots,
so, D=0
by quadratic formula,
D=b²-4ac
0=(-5)²-4(p)(p)
0=25-4p²
4p²=25
p²=25/4
p=±√25/4
p=5/4
the value of p is 5/4
hope this answer will help you.
where,
a=p
b=-5
c=p
and, it has two equal roots,
so, D=0
by quadratic formula,
D=b²-4ac
0=(-5)²-4(p)(p)
0=25-4p²
4p²=25
p²=25/4
p=±√25/4
p=5/4
the value of p is 5/4
hope this answer will help you.
ishitamogha21:
thanks
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