Question

Find the value of p for which the equation px2-5x+p=0 has equal roots

Answer 1

px²-5x+p
where,
a=p
b=-5
c=p
and, it has two equal roots,
so, D=0
by quadratic formula,
D=b²-4ac
0=(-5)²-4(p)(p)
0=25-4p²
4p²=25
p²=25/4
p=±√25/4
p=5/4

the value of p is 5/4

hope this answer will help you.