Math, asked by atishkumar5333, 10 months ago

Find the value of p for which the number 9783p29 is divisible by 9​

Answers

Answered by abhi178
2

We have to find the value of p for which the number 9783p29 is divisible by 9.

Solution : divisibility of 9 : a number must be divisible by 9 when sum of all digits of the number be the Integral multiple of 9.

for instance, 927936 is divisible by 9 or not ?

First add all digits. I.e., 9 + 2 + 7 + 9 + 3 + 6 = 36 = 4 × 9

did you see ? sum of all digits of 927936 is 36 which is integral multiple (i.e., 4 × 9) of 9

Hence 927936 is divisible by 9.

Now let's come to the question.

given, 9783p29 is divisible by 9

It means sum of all digits of 9783p29 = 9n , where n is integers

9 + 7 + 8 + 3 + p + 2 + 9 = 9n

⇒38 + p = 9n

if we put n = 5 [ because p must be one digit number and non negative ]

⇒38 + p = 45

⇒p = 7

Therefore the value of p is 7

Answered by 001857
1

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