Question

Find the value of p for which the numbers 2p-1, 3p+1, 11 are in AP. Hence, find the numbers.

Answer 1

Answer:

The given three numbers (2p - 1), (3p + 1) and 11 are in AP. So, the value of p is 2. i.e., 3, 7 and 11. 3, 7, 11.

Answer 2

QUESTION:-

Find the value of p for which the numbers 2p-1, 3p+1, 11 are in AP. Hence, find the numbers

ANSWER:-

If the numbers a,b and c are in AP, then

⟹ b - a = c - b

⇒ 2b = a + c

The given three numbers (2p-1),(3p+1) and 11 are in AP.

Then,

⟹ 2(3p+1)=(2p−1)+11

⇒6p + 2 = 2p − 1 + 11

⇒6p + 2 = 2p + 10

⇒6p − 2p = 10 − 2

⇒ 4p = 8

⇒P = 8/4

⇒ P = 2

So, the value of p is 2.

Then, the given numbers be-

⟹ (2×2−1),(3×2+1),11

⟹ 4−1) ,(6+1) ,11

⟹ 3,7,11