find the value of p for which the pair of linear equations 10x+3py-1=0,5x+3y-2=0 has exactly one solution
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Given: The pair of linear equations 10x + 3py - 1 = 0 , 5x + 3y - 2 = 0
To find: the value of p for which the pair of linear equations has exactly one solution.
Solution:
- Now we have given the equations as:
10x + 3py - 1 = 0 , 5x + 3y - 2 = 0
- The condition for exactly one solution is:
a1/a2 = b1/b2 ≠ c1/c1
- So applying this, we get:
10/5 = 3p/3 ≠ -1/-2
- Now equation first and second term, we get:
10/5 = 3p/3
p = 10/5
p = 2
Answer:
So the value of p is 2.
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