Question

Find the value of p for which the point.(-1,3) (2,p) (5,-1) colliniere

Answer 1

Answer:p=-1

Step-by-step explanation:

X1 (y2-y3)+x2 (y3-y1)+x3 (y1-y2)=0

-1 (p+1)+2 (-1-3)+5 (3-p)=0

-p-1-2-6+15-5p=0

-6p-6=0

-6p=0

P=-1