Find the value of p for which the points (-1, 3),
(2, p), (5, -1) are collinear.
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1
Answer:
'p' here it is
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-1 3 1
2 p 1 =0
5 -1 1
-1(p+1)-3(2-5)+1(-2-5p) =0
-p-1 +9 -2 -5p =0
-6p=-6
P=1
2 p 1 =0
5 -1 1
-1(p+1)-3(2-5)+1(-2-5p) =0
-p-1 +9 -2 -5p =0
-6p=-6
P=1
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