find the value of p for which the points (-5,1) , (1,p) , and (4,-2) are collinear.
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Answered by
588
Hi !
x₁ = -5
x₂ = 1
x₃ = 4
y₁ = 1
y₂ = p
y₃ = -2
For the points to be collinear :-
x₁(y₂ -y₃) + x₂(y₃ - y₂) + x₃(y₁ - y₂) = 0
-5{ p -(-2)} + 1 ( - 2 - 1) + 4( 1 - p) = 0
-5(p+2) + 1(-3) + 4( 1 - p) = 0
-5p - 10 - 3 + 4 - 4p = 0
-9p - 9 = 0
-9p = 9
p = 9/-9
p = -1
x₁ = -5
x₂ = 1
x₃ = 4
y₁ = 1
y₂ = p
y₃ = -2
For the points to be collinear :-
x₁(y₂ -y₃) + x₂(y₃ - y₂) + x₃(y₁ - y₂) = 0
-5{ p -(-2)} + 1 ( - 2 - 1) + 4( 1 - p) = 0
-5(p+2) + 1(-3) + 4( 1 - p) = 0
-5p - 10 - 3 + 4 - 4p = 0
-9p - 9 = 0
-9p = 9
p = 9/-9
p = -1
tom31:
my answer is also that
yeah
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