Question

Find the value of p for which the points - 5 11 p and minus 42 are collinear

Answer 1

Hi !

x₁ = -5

x₂ = 1

x₃ = 4

y₁ = 1

y₂ = p

y₃ = -2

For the points to be collinear :-

x₁(y₂ -y₃) + x₂(y₃ - y₂) + x₃(y₁ - y₂) = 0

-5{ p -(-2)} + 1 ( - 2 - 1) + 4( 1 - p) = 0

-5(p+2) + 1(-3) + 4( 1 - p) = 0

-5p - 10 - 3 + 4 - 4p = 0

-9p - 9 = 0

-9p = 9

p = 9/-9

p = -1

HOPE THIS HELPS....

@HARSHA

Answer 2

Answer:

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