Question

Find the value of 'p' for which the polynomial =:
$2x {}^{4 } + 3x {}^{3} + 2px {}^{2} + 3x + 6$
Is divisible by =:
$(x + 2)$
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

X+2=0

X=-2

Put,X=2 in the polynomial P(X)

=>2(-2)^4+3(-2)^3+2p(-2)^2+3(-2)+6=0

=>32-24+8p-6+6=0

=>8+8p=0

=>p=1

Thus,

if the value of P =1 than the polynomial P(X) is divisible by (X+2)

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