Question

Find the value of p for which the polynomial x3+4x2-px+8 is exactly divisible by x-2

Answer 1

Answer:

Step-by-step explanation:

P(x) = x^3+4x^2-px+8

P(2)= (2)^3+4(2)^2-p(2)+8=0

P(2)=8+16-2p+8=0

P(2)=32-2p=0

P(2)=-2p=-32

P=16