find the value of p for which the quadratic equation (2p + 1) x square - (7p + 2) X + (7p - 3)=0 has equal roots.Also find these roots.
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apply discriminant
I.e D = b^2-4ac
0 =(7p+2)^2-4(2p+1)(7p-3)
0 =49p^2+4+28p -4(14p^2-6p+7p-3)
0=49p^2+4+28p-56p^2+24p-28p+12
0= -7p^2+24p+16
now apply spilt methods of factorisation u .must get answer
I.e D = b^2-4ac
0 =(7p+2)^2-4(2p+1)(7p-3)
0 =49p^2+4+28p -4(14p^2-6p+7p-3)
0=49p^2+4+28p-56p^2+24p-28p+12
0= -7p^2+24p+16
now apply spilt methods of factorisation u .must get answer
vinaykotreb:
what is the last answer
what
i said solve it further
using factorisation
0=7p^2-24p-16
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