find the value of p for which the quadratic equation (2p+1) x^2 - (7p+2) x+ (7p-3 ) =0
adityajadhav192005:
hi
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Answered by
15
FOR DETERMINANT
D= b²-4ac
=>[-(7p+2)²]-4*(2p+1)*(7p-3)=0
HERE D= 0
then u have to solve it
49p+4+28p-(8p-3)*(7p-3)=0
BY SIMPLY SOLVING IT U CAN GET UR ANSWER
IF U DONT FIND ANSWER THEN I WILL TELL U
D= b²-4ac
=>[-(7p+2)²]-4*(2p+1)*(7p-3)=0
HERE D= 0
then u have to solve it
49p+4+28p-(8p-3)*(7p-3)=0
BY SIMPLY SOLVING IT U CAN GET UR ANSWER
IF U DONT FIND ANSWER THEN I WILL TELL U
Answered by
13
Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝
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