Find the value of p for which the quadratic equation 4x square + bx + 3 is equal to zero has roots
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Heya !!
4X² + BX + 3
Here,
A = 4 , B = B and C = 3
Discriminant ( D ) = 0
B²-4AC = 0
B² - 4 × 4 × 3 = 0
B² - 48 = 0
B² = 48
B = ✓48 = ✓2 × 2 × 2 × 2 × 3
B = 4✓3
4X² + BX + 3
Here,
A = 4 , B = B and C = 3
Discriminant ( D ) = 0
B²-4AC = 0
B² - 4 × 4 × 3 = 0
B² - 48 = 0
B² = 48
B = ✓48 = ✓2 × 2 × 2 × 2 × 3
B = 4✓3
Answered by
0
Your question needs a correction,
Correct Equation =4x² + px + 3 = 0
a = 4
b = p
c = 3
Discriminant = b² - 4ac
For real and equal roots, discriminant = 0
=> b² - 4( 4 × 3 ) = 0
=> b² = 48
=> b = ±√48
=> b = ±4√3
Correct Equation =4x² + px + 3 = 0
a = 4
b = p
c = 3
Discriminant = b² - 4ac
For real and equal roots, discriminant = 0
=> b² - 4( 4 × 3 ) = 0
=> b² = 48
=> b = ±√48
=> b = ±4√3
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