Question

find the value of p for which the quadratic equation 9x^-3px+p=0 has equal root​

Answer 1

Answer:

0 or 4

Step-by-step explanation:

Given that the equation has equal roots, means value of discriminant (b²-4ac) is equal to zero.

Here,

a=9, b=-3p, c=p

Thus,

b²-4ac = (-3p)²-4×9×p

But b²-4ac=0

Therefore,

9p²-36p=0

9p(p-4)=0

9p=0 or p-4=0

p=0 or p=4

Thus, the value of p for which the quadratic equation 9x^-3px+p=0 has equal root is 0 or 4.