Question

Find the value of p for which the quadratic equation to p + 1 into x square - 70 + 2 into x + 7 p.m. minus 3 equal to zero has equal roots also find this roots

Answer 1

Answer:

2p + 1)x² + (7p+2)x + (7p-3) = 0

If they have equal roots,

b²-4ac=0

Let,

a=2p+1

b=7p+2

c=7p-3

Now,

(7p+2)² - 4(2p + 1) (7p-3)=0

49p² +4+ 28p – 4(14p² +p-3)=0

After simplification,

7p²-24p+16=0

The roots are,

4 and -4/7.