Question

Find the value of p for which the quadratic equation x^2-2px+1=0 has no real roots

Answer 1

x²-2px+1=0
x²-2.x.1+(1)²=0
(x-1)²= 0
p = 1
is the correct answer ..

Answer 2

Answer:

Step-by-step explanation:

Apply discriminant

Bsquare-4ac

=4psquare-4*1*1

4psquare=4

Psquare=4/4

Psquare=1

P =√1

P=1

Answer 3

Answer:

Step-by-step explanation:

Apply discriminant

Bsquare-4ac

=4psquare-4*1*1

4psquare=4

Psquare=4/4

Psquare=1

P =√1

P=1

Answer 4

Answer:

Step-by-step explanation:

Apply discriminant

Bsquare-4ac

=4psquare-4*1*1

4psquare=4

Psquare=4/4

Psquare=1

P =√1

P=1