Question

find the value of p for which the quadratic equation (x2-px+4=0) has real roots​

Answer 1

Step-by-step explanation:

What r the roots ??????

Answer 2

Answer:

For a quadratic equation to have real roots, its discriminant should be greater than or equal to zero

ie, b²- 4ac ≥ 0                         (here, a = 1 , b = -p  and c = 4)

so , (-p)² - 4×1×4 ≥ 0

ie,   p² - 16 ≥ 0

ie,   p² ≥ 16

ie,   p ≥  ±4

HOPE THIS HELPS....