Question

find the value of p for which the roots of the quadratic equation PX bracket x minus 3 + bracket close + 9 is equals to zero have two equal roots

Answer 1

Pls find the answer here
The quadratic equation is
Px(x-3) + 9 =0
Px^2 -3px +9 =0
Here a=p
b=-3p
c= 9
b^2 - 4ac=0
(-3p)^2 -4(9)(p) =0
9p^2 - 36p = 0
9p( p -4 ) = 0
9p=0 or p-4=0
Therefore p=0 or p=4