Question

Find the value of “p” from the equation x²+3x+p, if one of the zeroes of the polynomial is 2.​

Answer 1

Answer:

put value of x

4+6+p =0

10+p=0

p=-10

Answer 2

$\huge\mathbb\purple{SOLUTION:-}$

◾Answer:-

• The required value of p is -10 .

◾Step-by-step explanation:-

• Given-

★ A polynomial, x² + 3x + p, where 2 is one of its zeroes.

• To Find-

★ The value of p.

• Solution-

★ Let p(x) = x² + 3x + p .....(1)

Now,

∵ 2 is one of the zeroes of the given polynomial,

∴ substituting 2 in the place of x and equating it with zero [since (x-2) is one of the factors of the polynomial] will give us the required value of p.

i.e.,

p(2) = (2)² + 3(2) + p = 0 [ From (1) ]

⇒p(2) = 4 + 6 + p = 0

⇒p(2) = 10 + p = 0

⇒p(2) = p = -10 (Ans.)

~ Hence, the required value of p is -10 .

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I hope this helps! : )