Math, asked by nehal7078, 1 year ago

Find the value of p , from the quadratic polynomial (p-1)^2 + 2px + 5 whose one of the zeroes is 5.​

Answers

Answered by BraɪnlyRoмan
112

\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}

GIVEN :

 \sf{p(x) =  \:  {(p - 1)}x^{2}  + 2px + 5}

One of the zeroes of p(x) = 5

TO FIND :

Value of p

SOLUTION :

 \sf{p(x) =  \:  {(p - 1)}x^{2}  + 2px + 5= 0}

Putting one of the zeroes, on p(x)

 \sf{p(5) =  \:  {(p - 1)}5^{2}  + 2(5)p + 5= 0}

 \sf {\implies \: 25p - 25 + 10p + 5 = 0}

 \sf {\implies \: 35p - 20 = 0}

  \sf{\implies \: 35p = 20}

 \sf {\implies \: p =  \frac{20}{35} }

 \sf{ \implies \: p =  \frac{4}{7 }}

 \boxed{ \sf{Hence, p =  \frac{4}{7}}}

Answered by palak932995
1

P=

  \frac{4}{7}

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