find the value of p if (2 3) is th the solution of (p+1) x-y=1
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The given pair of linear equation :
⇒ (p+2)x−(2p+1)y=3(2p−1) ------ ( 1 )
⇒ 2x−3y=7 ------- ( 2 )
On comparing with equations,
a1x+b1y+c1=0
and a2x+b2y+c2=0
We get, a1=(p+2),b1=−(2p+1),c=−[3(2p−1)]
a2=2,b2=−3,c=−7
⇒ a2a1=2p+2 and b2b1=−3−(2p+1)
A pair of linear equations has a unique solution, if
⇒ a2a1
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