Question

Find the value of p, if (-2)^p+1*(-2)^p=-8

Answer 1

Answer:

GIVEN THAT :-

${( - 2)}^{p + 1} \times {( - 2)}^{p} = - 8$

WE KNOW THAT -

${a}^{n} \times {a}^{m} = {a}^{m + n}$

SO,

${( - 2)}^{2p + 1} = - 8$

WE SHOULD WRITE THIS AS -

${( - 2)}^{2p + 1} = {( - 2)}^{3}$

COMPARE -

=》

$2p + 1 = 3$

=》

$p =1$

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