English, asked by shreyan94, 9 months ago

find the value of p if 2x^3 - 5x^2 + px - 7 = 10 , x = -1​

Answers

Answered by cblankenship23
0

Answer:

p = 0

Explanation:

2x^3 - 5x^2 + px - 7 = 10

2(-1)^3 - 5(-1)^2 + p(-1) - 7 = 10

(-2)^3 - (-5)^2 + (-p) - 7 = 10

-8 + 25 + (-p) - 7 = 10

10 (-p) = 10

p = 0

Answered by Bhosale2002
1

Answer:

-24

Explanation:

2 {x}^{3}  - 5 {x}^{2}  + px - 7 = 10

but we have given,

x = -1

2 \times   { - 1}^{3}  - 5 \times  { - 1}^{2}  + p \times ( - 1) - 7 = 10

 2 \times  - 1 - 5 \times 1  - p - 7 = 10

 - 2 - 5 - p - 7 = 10

 - 14 - p = 10

 - p = 10 + 14

 - p = 24

p =  - 24

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