Find the value of p if (3,2)is the solution of px-5y+p^2
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Answer:
Substitute the x and y values in:
p^2 + 3p - 5(2) = 0
p^2 + 3p - 10 = 0
Factorise this:
(p - 2)(p + 5)
p = 2
p = -5
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