Question

FIND THE VALUE OF P IF (4-7)9+(4_7)2=(4-7)2P-1

Answer 1

(-3)9+(-3)2=(-3)2p-1 -27-6=-6p-1 => -33+1=6p -32=6p => -32/6=p

Answer 2

Answer:

The value of P is $P = \frac{32}{6}$ .

Step-by-step explanation:

As the expression is given in the question be as follow

(4-7)9+(4-7)2=(4-7)2P-1

It is written as

(4-7) × 9+(4-7) × 2=(4-7) × 2P-1

First solve the terms inside the bracket and than open the bracket

-3 × 9 - 3 × 2 = -3 × 2P-1

-27 - 6 = -6P - 1

-27 - 6 + 1 = -6P

- 27 -5 = -6P

$P = \frac{-32}{-6}$

$P = \frac{32}{6}$

Therefore the value of P is $P = \frac{32}{6}$ .