Question

Find the value of p, if -4 is zero of polynomial p(x)=x^2-2x-(7p+3)

Answer 1

p(-4)=(-4)^2-2(-4)-(7p+3)
=16+8-7p-3
=-7p+21
p(-4) =0
-7p+21=0
7p=21
p=3

Answer 2

Answer

$\sf{If -4 \: is \: zero \: of \: given \: polynomial \: then} \\ \\(−4)2−2(−4)−(7p+3)=0 \\ \\ ⇒16+8−7p−3=0 \\ \\ ⇒7p=21 \\ \\ ⇒p=3$