Question

find the value of p if​

Answer 1

Answer:

p = 4

Step-by-step explanation:

Given,

${( \frac{2}{5}) }^{3} \times {( \frac{2}{5} ) }^{6} = {( \frac{2}{5} )}^{2p + 1}$

Since,

${a}^{x} \times {a}^{y} = {a}^{x + y}$

Then,

$= > {( \frac{2}{5}) }^{3 + 6} = {( \frac{2}{5}) }^{2p + 1}$

As the bases are same,

=> 3 + 6 = 2p + 1

=> 9 = 2p + 1

=> 9 - 1 = 2p

=> 2p = 8

$= > p = \frac{8}{2}$

=> p = 4 (Ans)