Question

find the value of p if area of triangle having vertex (1,p) (2,4) (3,1) is 12 unit
I will mark right answer as brain list​

Answer 1

Answer:

A(p,2p), B(−2,b), C(3,1)

BC=

(−2−3)

2

+(6−1)

2

=5

2

units

Slope of BC=

−2−3

6−1

=

−5

5

=−1

Now, A line on 2 line parallel to BC at a distance

2

from BC

Let equation of reqd line is y=−x+c

⇒ x+y−c=0

Equation of BC=x+y−4=0

2

=

2

∣4−C∣

⇒2=∣4−C∣⇒C=2 or 6

A lies on the line

∴ p+2p−2=0 or p+2p−6=0

⇒ 3p−2=0 or 3p=6⇒p=2

⇒p=2/3 or 2.