Question

find the value of p if following quadratic equation have equal roots 4 x square (p - 2)x + 1 = 0​

Answer 1

GOOD MORNING!!

For Equal roots Descrimnant = 0

Given Quadratic Equation is

4x² + (p - 2)x + 1 = 0

Descrimnant (D) of given Quadratic Equation is (p - 2)² - 4 (4) (1)

D = p² + 4 - 4p - 16

D = 0 For Equal roots.

So,

p² - 4p - 12 = 0

p² - 6p + 2p - 12 = 0

p ( p - 6 ) + 2 ( p - 6 ) = 0

( p + 2 ) × ( p - 6 ) = 0

p = -2 OR p = 6

So, Possible values of p are -2 and 6