Question

find the value of p if one of the root of quadratic equation 5x² + (3p+2)x + 15 = 0 is 5​

Answer 1

Given x=5,

Putting x=5 in the given equation..

5(5)²+(3p+2)(5)+15=0

=> 5(25)+15p+10+15=0

=> 125+15p+25=0

=> 15p+150=0

=> 15p= -150

=> p=$\frac{-150}{15}$

=> p= -10

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Answer 2

Answer: -10

Step-by-step explanation:

5x^2+(3p+2)x+15=0

put value of (x=5) in equation

5(5)^2 +(3p+2)5+15=0

125 +15p +10 +15=0

15p+150=0

15p= -150

p=-10

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