Find the value of p if p -1, p + 3 and 3p -1 are in AP.
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Step-by-step explanation:
let p-1 be a1 , p + 3 be a2 and 3p-1 be a3
we know a2-a1 =d
also a3 -a2 =d
therefore a2 - a1 = a3 - a2
that is p + 3 - (p - 1 ) = 3p - 1 - ( p + 3)
p + 3 - p +1 = 3p - 1 -p -3
p- p + 3+ 1 = 3p - p - 1 - 3
3+ 1 = 2p -4
4 = 2p - 4
that is 2p - 4 = 4
2p = 4 + 4
2 p = 8
p = 8/2
p = 4
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Answered by
1
Your answer is
p=4
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