Question

Find the value of P. If polynomial f(x) = px^2 + 4x + 3x – 4 and g(x) = x^2 + 4 + p are divided by (x – 3), then remainder in each case is same.​

Answer 1

Answer:

iven ax

3

+4x

2

+3x−4=0 &

x

3

−4x+a=0 leave same

remainder when divided by x-3

P(x) = ax

3

+4x

2

+3x−4

q(x)= x

3

−4x+a

Remainder theorem,

P(3)=q(3)

a(3)

3

+4(3)

2

+3(3)−4=3

3

−4(3)+a

27a+36+9−4=27−12+a

26a=15−41

26a=−26

∴a=−1

P(x)=−x

3

+4x

2

+3x−4

when divide by (x-2)

P(2)=−(2)

3

+4(2)

2

+3(2)−4

=−8+16+6−4

=8+2

=10

Answer 2

xif xịf =

Mean=

Exfi

214 + 9p

P +21

9p + 214