Question

Find the value of 'p' if px + 4y-3=0 and x+2y+4=0 are
parallel lines ?​

Answer 1

Answer:

for parallel lines slope of both the equations will be equal

Step-by-step explanation:

for eq 1:

4y=3-px

y=3-p×/4

slope (m1)=-p/4

for eqn 2:

2y = -4-×

y =-4-×/2

slope(m2)=-1/2

m1=m2

-p/4=-1/2

p=2

Answer 2

The value of p=2

Step-by-step explanation:

$px+4y-3=0$

$x+2y+4=0$

$a_1=p,b_1=4,c_1=-3$

$a_2=1,b_2=2,c_2=4$

Condition of parallel lines

$\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}$

$\frac{p}{1}=\frac{4}{2}\neq \frac{-3}{4}$

Taking first equality

$\frac{p}{1}=\frac{4}{2}$

$p=2$

Hence, the value of p=2

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