Question

Find the value of p if st line 3u+py-1=0,
7x-3y+3=0 are mutually
perpendicular​

Answer 1

p = 7

Step-by-step explanation:

if 2 lines are perpendicular their product of slop = -1

m1*m2 = -1

now first line = 3x+py-1=0

it can be written as

y =  -  $\frac{3}{p}$ x +(1/p)  ........................................eq 1

comparing with y=mx+c

m1 = -  $\frac{3}{p}$   .............................................eq 2

now  second line i= 7x-3y+3

         it can be written as

y =  $\frac{7}{3}$ x + (3/3)........................................eq 3

comparing with y=mx+c

m1 =  $\frac{7}{3}$  .............................................eq 4

using eq 3 and 4

m1*m2 = -1

-  $\frac{3}{p}$ * $\frac{7}{3}$   = -1

p = 7