Question

Find the value of p, if $27^{p}=\frac{9}{3^{p}}$

Answer 1

27^p=9/3^p

(3³)^p=3²/3^p

now use the identities (a^m)^n=a^mn

a^m/a^n=a^m-n

so,

3^3p=3^2-p

as the bases are equal powers must be equal so now equate the powers and remove the bases.

3p=2-p

4p=2

p=2/4

p=1/2

Answer 2

Answer:

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