Question

find the value of P If the equation
$3x { }^{2} - 2x + p = 0$
and
$6x {}^{2} - 17x + 12 = 0$
have common roots​

Answer 1

Answer:

$3 {x}^{2} - 2x + p = 6 {x}^{2} - 17x + 12 \\ or \: 3 {x}^{2} - 2x + p - 6 {x}^{2} + 17x - 12 = 0 \\ or \: - 3 {x}^{2} + 15x - 12 + p = 0 \\ or \: p = 3 {x}^{2} - 15x + 12 \\ or \: p = 3 {x}^{2} - 12x - 3x + 12 \\ or \: p = 3x(x -4 ) - 3(x - 4) \\ or \: p = (x - 4)(3x - 3)$

Answer 2

Answer:

3x

2

−2x+p=6x

2

−17x+12

or3x

2

−2x+p−6x

2

+17x−12=0

or−3x

2

+15x−12+p=0

orp=3x

2

−15x+12

orp=3x

2

−12x−3x+12

orp=3x(x−4)−3(x−4)

orp=(x−4)(3x−3)